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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionMedium2 minQB

PhysicsMediumsingle choice

A soap bubble of radius $R$ is surrounded by another soap bubble of radius $2 R$ , as shown. Take surface tension = $S$ . Then the pressure inside the smaller soap bubble, in excess of atmospheric pressure, will be

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Answer:

Solution:

$P_{1} - P_{0} = \frac{4 S}{2 R} = \frac{2 S}{R}$
$P_{2} - P_{1} = \frac{4 S}{R}$
Adding the two pressure differences,
$P_{2} - P_{0} = \frac{6 S}{R}$

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: QB

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