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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionEasy2 minQB

PhysicsEasysingle choice

A soap bubble has radius $R$ and thickness $d (< < R)$ as shown in the diagram. It collapses into a spherical drop. The ratio of excess pressure in the drop to the excess pressure inside the bubble is

Options:

Answer:

Solution:

The volume of soap solution in a bubble $= 4 π R^{2} d$
now we make a drop

$4 π R^{2} d = \frac{4}{3} π r^{3} \Rightarrow r = {(3 R^{2} d)}^{1 / 3}$

Excess pressure initially $= \frac{4 S}{R}$

Excess pressure finally $= \frac{2 S}{r} = \frac{2 S}{{(3 R^{2} d)}^{1 / 3}}$

Ratio $= {(\frac{R}{24 d})}^{\frac{1}{3}}$

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: QB

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