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If the radius of the opening of the dropper is r , the vertical force due to the surface tension on the drop of radius $R$ (assuming $r ≪ R$ ) is

Answer:

Solution:

$F_{T} = T \cdot 2 π r F_{V} = F_{T} sin θ = T \cdot 2 π r \cdot \frac{r}{R} = \frac{2 π r ^{2} T}{R}$

Stream:JEESubject:PhysicsTopic:Fluid

⏱ 2mℹ️ Source: QB

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