For the arrangement shown in the figure, the time interval in seconds after which the water jet ceases to cross the wall is found to be ( α ) 3 . Area of the cross section of the tank A = 5 m 2 and

Question

For the arrangement shown in the figure, the time interval in seconds after which the water jet ceases to cross the wall is found to be $(α)^{3}$ . Area of the cross section of the $tank A = 5 m^{2}$ and area of the orifice a $= 32 cm^{2}$ . [Assume that the container remaining fixed]. Find the value of $α$ . (Take $g = 10 m / s^{2}$ )

TestHub · Accepted Answer

( v m i n ​ ) × g 2 h ​ ​ = 1 ⇒ v m i n ​ = 5 ​ m / s This will give us the minimum height for this velocity: 2 gh m i n ​ ​ = 5 ​ ⇒ h m i n ​ = 4 1 ​ m = 0.25 m . We have v 1 ​ = 2 gh ​ and v 2 ​ = − dh / dt . av 1 ​ = Av 2 ​ . a 2 gh ​ = A ( − dt dh ​ ) ⇒ ∫ 0.81 0.25 ​ h ​ dh ​ = ∫ 0 t ​ A ( a 2 g ​ ) ​ dt This leads to t = 125 sec = ( 5 ) 3 = ( a ) 3 ⇒ α = 5 .

Physics - Fluid Question with Solution | TestHub

Doubts & Discussion