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Physics - Fluid Question with Solution | TestHub

PhysicsFluidPressureMedium3 minQB

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Passage / Comprehension

A U-tube with liquids of densities $ρ$ and $2 ρ$ stands vertically on a rotating table.
Its rotation axis passes through the table centre. Initially the interface is at A, the liquid column above A is $8 a /3$ , and $A B = 2 a$ .
The tube has cross-sectional area S. At angular speed $ω$ , the interface shifts $2 a /3$ toward B. Use the shown geometry for Q16 to Q18.

Find $P_{B} - P_{A}$ .

Options:

Answer:

Solution:

$P_{B} - P_{A} = (2 a) (2 ρ g) - (2 a) (ρ g)$
$P_{B} - P_{A} = 2 a ρ g$

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Pressure

⏱ 3mℹ️ Source: QB

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