Physics - Fluid Question with Solution | TestHub

The pressure $P$ at a depth $h$ below the surface of a fluid of density $\rho$ is given by

$P=P_0+\rho gh$

Given that the pressure at depth $h$ is $n$ times the atmospheric pressure, we have

$P=n{P}_0$

Substituting this into the pressure equation gives

$n{P}_0=P_0+\rho gh$

$\rho gh=n{P}_0-P_0$

$\rho gh=(n-1)P_0$

$h=\frac{(n-1)P_0}{\rho g}$

Answer: $\frac{(n-1)P_0}{\rho g}$