Water rises to a height of 2.2 cm in glass capillary tube. The height to which water will rise in another capillary having one-fourth area of cross-section as that of the first is.

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The height of capillary rise is given by $h = \frac{2 T cos θ}{ρ g r}$

This implies $h \propto \frac{1}{r}$

The area of cross-section is $A = π r^{2}$

Given $A_{2} = \frac{A _{1}}{4}$ , we get $r_{2} = \frac{r _{1}}{2}$

Therefore, $h_{2} = h_{1} \times \frac{r _{1}}{r _{2}} = 2.2 \times 2 = 4.4$ cm

Answer: $4.4$ cm

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