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PhysicsFluidBernoulli's theorem and applicationsEasy2 minPYQ_2026

PhysicsEasysingle choice

For a liquid at rest of density $ρ$ , what is the increase in pressure at a depth h below the free surface (take g as acceleration due to gravity)?

Options:

Answer:

Solution:

Let the pressure at the free surface of the liquid be $P_{0}$ .

The pressure at a depth $h$ below the free surface of a liquid of density $ρ$ at rest is given by $P = P_{0} + ρ g h$ .

The increase in pressure at depth $h$ is $Δ P = P - P_{0} = ρ g h$ .

Answer: $ρ g h$

Stream:MHT_CET_MEDICALSubject:PhysicsTopic:FluidSubtopic:Bernoulli's theorem and applications

⏱ 2mℹ️ Source: PYQ_2026

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