Physics - Fluid Question with Solution | TestHub

Let the total volume of the ice cube be $V$ and the volume submerged in water be $V_{in}$.

By the principle of flotation, the weight of the ice cube is equal to the buoyant force.

$V{\rho }_{i}g=V_{in}{\rho }_{w}g$

$V_{in}=V\frac{{\rho }_i}{{\rho }_w}$

Substituting the given densities ${\rho }_i=0.9$ g/cc and ${\rho }_w=1$ g/cc:

$V_{in}=V\frac{0.9}{1}=0.9V$

The volume of the ice cube outside the water is:

$V_{out}=V-V_{in}=V-0.9V=0.1V$

The percentage of volume outside the water is:

$\frac{V_{out}}{V}\times 100=\frac{0.1V}{V}\times 100=10\%$

Answer: $10\%$