A solid steel ball of diameter 3.6 mm acquired terminal velocity 2.45 × 1 0 − 2 m / s while falling under gravity through an oil of density 925 kg m − 3 . Take density of steel as 7825 kg m − 3 and g

Question

A solid steel ball of diameter 3.6 mm acquired terminal velocity 2.45 × 1 0 − 2 m / s while falling under gravity through an oil of density 925 kg m − 3 . Take density of steel as 7825 kg m − 3 and g as 9.8 m / s 2 . The viscosity of the oil in SI unit is

TestHub · Accepted Answer

v T ​ ⇒ 9 2 ​ η ( ρ 0 ​ − ρ ℓ ​ ) r 2 g ​ ​ η = 9 2 ​ ( 2.45 × 1 0 − 2 7825 − 925 ​ ) × ( 1.8 ) 2 × 1 0 − 6 × 9.8 η ≈ 1.99 ​

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