Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionMedium2 minPYQ_2025

PhysicsMediumsingle choice

The amount of work done to break a big water drop of radius ' $R$ ' into 27 small drops of equal radius is 10 J . The work done required to break the same big drop into 64 small drops of equal radius will be

Options:

Answer:

Solution:

$W_{1} = s 4 π (\frac{R}{3})^{2} \times 27 - 4 π R^{2} \cdot s \Rightarrow W_{1} = 4 π R^{2} \cdot s (2) = 10 Joule$ Now, $W_{2} = s 4 π R^{2} (4 - 1) = 4 π R^{2} s \times 3$ $\Rightarrow W_{2} = 3 \times \frac{10}{2} = 15 Joule$

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2025

Doubts & Discussion

Loading discussions...