Physics - Fluid Question with Solution | TestHub

The height of the liquid column in a capillary tube is given by Jurin's law:

$h=\frac{2T\cos \theta }{r\rho g}$

where $T$ is the surface tension, $\theta$ is the angle of contact, $r$ is the radius of the capillary tube, $\rho$ is the density of the liquid, and $g$ is the acceleration due to gravity.

Given that the angle of contact $\theta =90^{\circ }$.

Substituting $\theta =90^{\circ }$ in the formula, we get:

$h=\frac{2T\cos 90^{\circ }}{r\rho g}$

Since $\cos 90^{\circ }=0$, we have:

$h=0$

Thus, the liquid will neither rise nor fall in the capillary tube.

Answer: neither rise nor fall.