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Physics - Fluid Question with Solution | TestHub

PhysicsFluidViscosityMedium2 minPYQ_2023

PhysicsMediumsingle choice

A spherical metal ball of radius ' $r$ ' falls through viscous liquid with velocity ' $V$ '. Another metal ball of same material but of radius $(\frac{r}{3})$ falls through same liquid, then its terminal velocity will be

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Answer:

Solution:

$v = \frac{2 r ^{2} ( ρ - σ ) g}{9Δ}$ $ρ, σ$ and $η$ are constant $\Rightarrow v \propto r^{2}$ The ratio of terminal velocities is $\frac{v _{1}}{v _{2}} \frac{v _{1}}{v _{2}} \frac{v _{1}}{v _{2}} ∴ v_{2} = \frac{r _{1}^{2}}{r _{2}^{2}} = \frac{r ^{2}}{( \frac{r}{3} ) ^{2}} = 9 = \frac{v}{9}$

Stream:MHT_CETSubject:PhysicsTopic:FluidSubtopic:Viscosity

⏱ 2mℹ️ Source: PYQ_2023

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