A shown in the figure, a liquid is at same levels in two arms of a U-tube of uniform cross-section when at rest. If the $U$ -tube moves with an acceleration ' $f$ ' towards right, the difference between liwuid height between two arms of the $U$ -tube will be, (acceleration due to gravity $= g$ )

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A

Solution:

Hint :
$tan θ = \frac{acceleration}{g} \frac{h}{a} = \frac{acceleration}{g} \frac{h}{a} = \frac{f}{g} h = \frac{fa}{g}$

TestHub · Accepted Answer

Hint : ​ tan θ = g acceleration ​ a h ​ = g acceleration ​ a h ​ = g f ​ h = g fa ​ ​

Physics - Fluid Question with Solution | TestHub

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