Figure below shows a liquid being pushed out of the tube by a piston having area of cross section $2.0 {cm}^{2}$ . The area of cross section at the outlet is $10 {mm}^{2}$ . If the piston is pushed at a speed of $4 cm s^{- 1}$ , the speed of outgoing fluid is _____ $cm s^{- 1}$

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TestHub · Accepted Answer

The given data is A 1 = 2 × 10 - 4 m 2 A 2 = 10 × 10 - 6 m 2 v 1 = 4 cm s - 1 Using equation of continuity which is a conservation of mass principle, A 1 v 1 = A 2 v 2 ⇒ v 2 = A 1 v 1 A 2 = 2 × 10 - 4 × 4 10 × 10 - 6 = 80 cm s - 1

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