Physics - Fluid Question with Solution | TestHub

For water not to fall off the can, then centrifugal force must balance the weight of water, $\therefore \frac{m{v}^2}{r}\ge mg$ Minimum speed of the can so that water does not fall down is given by, $v=\sqrt{rg}$ Time period of revolution, $T=\frac{2\pi r}{v}=2\pi \sqrt{\frac{r}{g}}$