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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionMedium2 minPYQ_2021

PhysicsMediumsingle choice

In capillary tube having area of cross-section ' $A$ ', water rises to a height ' $h$ '. If cross sectional area is reduced to $\frac{A}{9}$ , the rise of water in the capillary tube is

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Solution:

$h = \frac{2 T cos θ}{r ρ g} \Rightarrow h \propto \frac{1}{r} And A = π r^{2} \Rightarrow r \propto A \Rightarrow h \propto \frac{1}{A} Now, \frac{h _{2}}{h _{1}} = \frac{A _{1}}{A _{2}} \Rightarrow \frac{h _{2}}{h} = \frac{A}{A /9} = 3 \Rightarrow h_{2} = 3 h$

Stream:MHT_CETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2021

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