Physics - Fluid Question with Solution | TestHub

Rise in a capillary tube is given by $$\begin{array}{rl}& \mathrm{h}=\frac{2\mathrm{T}\cos \theta }{\mathrm{r}\rho \mathrm{g}}\\ & \therefore \mathrm{h}\propto \frac{1}{\mathrm{g}}\end{array}$$ Smaller the value of $g$. greater will be h. Out of the given options, value $g$ will be minimum for option (A)