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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionEasy2 minPYQ_2020

PhysicsEasysingle choice

Two soap bubbles of radii $3 mm$ and $4 mm$ confined in vacuum coalesce isothermally to form a new bubble. The radius of the bubble formed $(in mm)$ is

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Answer:

Solution:

$P_{1} V_{1} + P_{2} V_{2} = P V$

$P_{1} - 0 = \frac{4 S}{R_{1}} \Rightarrow P_{1} R_{1} = 4 S$

Similarly $P_{2} R_{2} = 4 S = P R$

$P_{1} \frac{4}{3} π R_{1}^{3} + P_{2} \frac{4}{3} π R_{2}^{3} = P \frac{4}{3} π R^{3}$

$R_{1}^{2} + R_{2}^{2} = R^{2}$

$R = 5 mm$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2020

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