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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionEasy2 minPYQ_2020

PhysicsEasysingle choice

The excess pressure inside a spherical drop of water is three times that of another drop of water. The ratio of their surface area is

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Solution:

Excess pressure $p = \frac{2 T}{r}$ $\frac{p _{1}}{p _{2}} = \frac{r _{2}}{r _{1}} = 3$ $∴ r_{2} = 3 r_{1} \frac{A _{1}}{A _{2}} = \frac{π r _{1}^{2}}{π r _{2}^{2}} = (\frac{r _{1}}{r _{2}})^{2} = \frac{1}{( 3 ) ^{2}} = \frac{1}{9}$

Stream:MHT_CETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2020

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