Physics - Fluid Question with Solution | TestHub

PhysicsFluidViscosityEasy2 minPYQ_2020
PhysicsEasysingle choice

We have two (narrow) capillary tubesT1andT2. Their lengths arel1andl2and radii of the cross-section arer1andr2respectively. The rate of water under a pressure differencePthrough tubeT1is 8 cm3 s-1. Ifl1 = 2l2andr1=r2, what will be the rate of flow when the two tubes are connected in series and the pressure difference across the combination is same as before(=P)

Options:

Answer:
B
Solution:

V=πPr48ηl=8 cm3 s-1

For composite tube

V1=Pπr48η(l+l2)=23πPr48ηl=23×8=163 cm3 s-1∴l1=l=2l2orl2=l2

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:FluidSubtopic:Viscosity
⏱ 2mℹ️ Source: PYQ_2020

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