The excess pressure inside the first soap bubble of radius ' R 1 ' is two times, that inside the second soap bubble of radius ' R 2 '. The ratio of volumes of the first bubble

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The excess pressure inside the first soap bubble of radius ' R 1 ​ ' is two times, that inside the second soap bubble of radius ' R 2 ​ '. The ratio of volumes of the first bubble to that of second bubble is

TestHub · Accepted Answer

Excess pressure P = R 4 T ​ ∴ P 2 ​ P 1 ​ ​ = R 1 ​ R 2 ​ ​ P 2 ​ P 1 ​ ​ = 2 V 2 ​ V 1 ​ ​ = 3 4 ​ π R 2 3 ​ 3 4 ​ π R 1 2 ​ ​ = R 2 3 ​ R 1 3 ​ ​ = ( 2 1 ​ ) 3 = 8 1 ​

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