There are two identical small holes of area of cross-section $A$ on the opposite sides of a tank containing a liquid of density $ρ$ . The difference in height between the holes is $h$ . Tank is resting on a smooth horizontal surface, horizontal force which has to be applied on the tank to keep it in equilibrium is

Question

TestHub · Accepted Answer

Rate of change of momentum = d p d t F = F Q - F P = d p Q d t - d p P d t = d m d t Q × V Q - d m d t P × V P = A ρ v Q × v Q - A ρ v P × v P = A ρ v Q 2 - v P 2 ...(i) P P + 1 2 ρ v P 2 + ρ g h = P Q + 1 2 ρ v Q 2 + 0 ∵ P P = P Q ⇒ 1 2 ρ v Q 2 - v P 2 = ρ g h ∴ F = 2 A ρ g h (from (i))

Physics - Fluid Question with Solution | TestHub

Options:

Doubts & Discussion