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PhysicsFluidBernoulli's theorem and applicationsEasy2 minPYQ_2020

PhysicsEasysingle choice

Water is flowing through a tube of non-uniform cross-section. If the radii of the tube at the entrance and exit are in the ratio $3 : 2$ , then the ratio of the velocity of liquid entering and leaving the tube is

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Answer:

Solution:

Using equation of continuity

$A_{1} v_{1} = A_{2} v_{2} \Rightarrow π r_{1}^{2} v_{1} = π r_{2}^{2} v_{2}$

$\Rightarrow \frac{v_{1}}{v_{2}} = \frac{r_{2}^{2}}{r_{1}^{2}} = {(\frac{2}{3})}^{2} = \frac{4}{9}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:FluidSubtopic:Bernoulli's theorem and applications

⏱ 2mℹ️ Source: PYQ_2020

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