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PhysicsFluidViscosityEasy2 minPYQ_2020

PhysicsEasysingle choice

The terminal velocity $v$ of a spherical ball of lead of radius $R$ falling through a viscous liquid varies with $R$ such that

Answer:

Solution:

The terminal velocity is given by :

$v = \frac{2 r^{2} (ρ - ρ_{0}) g}{9 η}$

Or $\frac{v}{r^{2}} = \frac{2 (ρ - ρ_{0}) g}{9 η} =$ constant

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:FluidSubtopic:Viscosity

⏱ 2mℹ️ Source: PYQ_2020

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