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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionEasy2 minPYQ_2020

PhysicsEasysingle choice

In a capillary tube having area of cross-section $A$ , the water rises to a height $h$ . If the cross-sectional area is reduced to $\frac{A}{9}$ , the rise of water in the capillary tube is

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Answer:

Solution:

$A_{1} = π r_{1}^{2}$

$A_{2} = π r_{2}^{2}$

$\frac{π r_{1}^{2}}{9} = π r_{2}^{2}$

$\frac{r_{1}^{2}}{r_{2}^{2}} = 9 \Rightarrow \frac{r_{1}}{r_{2}} = 3$

$r h =$ constant

$r_{1} h_{1} = r_{2} h_{2}$

$\frac{r_{1}}{r_{2}} = \frac{h_{2}}{h_{1}}$

$3 = \frac{h_{2}}{h_{1}} = \frac{h_{2}}{h_{1}}$

$h_{2} = 3 h_{1} = 3 h$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2020

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