Physics - Fluid Question with Solution | TestHub

The excess of pressure due to surface tension on a spherically liquid drop is given by
$p=\frac{2T}{R}$….(i)
where, T = surface tension
and R = radius of liquid drop.
So, from Eq. (i), we get
$p\propto \frac{1}{R}orp\propto R^{-1}$