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PhysicsFluidArchimedes principleMedium2 minPYQ_2019

PhysicsMediumsingle choice

A cubical block of side $0.5 m$ floats on water with $30 %$ of its volume under water. What is the maximum weight that can be put on the block without fully submerging it under water?

[Take, density of water $= 10^{3} k g / m^{3}$ ]

Options:

Answer:

Solution:

In first case, when $30 %$ of the cube inside water,
$ρ_{w} V_{i n} g = ρ_{c} V g$
$\frac{V_{i n}}{V} = \frac{ρ_{c}}{ρ_{w}} = 0.3$
Additional weight we can put $w$ is,
$V ρ_{w} g = ρ_{c} V g + w$
$w = V (ρ_{w} - ρ_{c}) g$
$= {(0.5)}^{3} \times 0.7 \times 10^{3} \times g$
$= 87.5 g N$
Addition of mass that we can put $= 87.5 k g$

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Archimedes principle

⏱ 2mℹ️ Source: PYQ_2019

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