Physics - Fluid Question with Solution | TestHub

Let V and $\rho$ be volume and density of solid respectively and ${\rho }^{\prime }$ be the density of water i.e., ${\mathrm{p}}^{\prime }=10^3\mathrm{kg}{\mathrm{m}}^{-3}$ Weight of body $=\mathrm{V}\rho g$ Volume of solid body outside water $=\mathrm{V}/4$ $\therefore$ Volume of solid body inside water $=\mathrm{V}-\mathrm{V}/4=3\mathrm{V}/4$ Weight of water displaced by solid $=\frac{3\mathrm{V}}{4}\times 10^3\times \mathrm{g}$ As solid body is floating, then Weight of body $=$ Weight of water displaced by it $\begin{array}{rl}\mathrm{V}\rho g& =\frac{3\mathrm{V}}{4}\times 10^3\mathrm{g}\\ \rho & =\frac{3}{4}\times 1000=750{\mathrm{kgm}}^{-3}\end{array}$