A rectangular film of liquid is extended from ( 4 cm × 2 cm ) to ( 5 cm × 4 cm ) . If the work done is 3 × 10 - 4 J , the value of the surface tension of the liquid isNEET 2016 (Phase 2)

W = 2 A f - A i T ⇒ T = W A f - A i × 2 = 3 × 10 - 4 J 2 5 × 4 × 10 - 4 - 4 × 2 × 10 - 4 = 0.125 N m - 1

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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionEasy2 minPYQ_2016

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A rectangular film of liquid is extended from $(4 cm \times 2 cm)$ to $(5 cm \times 4 cm)$ . If the work done is $3 \times 10^{- 4} J$ , the value of the surface tension of the liquid isNEET 2016 (Phase 2)

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Answer:

Solution:

$W = 2 (A_{f} - A_{i}) T$

$\Rightarrow T = \frac{W}{(A_{f} - A_{i}) \times 2}$

$= \frac{3 \times 10^{- 4} J}{2 [5 \times 4 \times 10^{- 4} - 4 \times 2 \times 10^{- 4}]}$

$= 0.125 N m^{- 1}$

Stream:NEETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2016

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