Physics - Fluid Question with Solution | TestHub

PhysicsFluidViscosityHard2 minPYQ_2015
PhysicsHardmultiple choice

Two spheres P and Q of equal radii have densities ρ1 and ρ2 , respectively. The spheres are connected by a massless string and placed in liquids L1 and L2 of densities σ1 and σ2 and viscosities η1 and η2 , respectively. They float in equilibrium with the sphere P in L1 and sphere Q in L2 and the string being taut (see figure). If sphere P alone in L2 has terminal velocity V→P and Q alone in L1 has terminal velocity V→Q , then

Options:(select one or more)

Answer:
A, D
Solution:

Consider a body of density ρb kept in density ρl whose viscosity is η and terminal velocity V. then



F→viscous +F→mg+F→Buoyancy=0
F→viscous+ρb43πR3-j^+ρl43πR3j^=0
∴ F→viscous=ρb-ρl43πR3j^⇒6πηRV=ρb-ρl43πR3 
∴ if ρb>ρ1 then F→viscous↑V∝1η & if ρb<ρl
F→viscous ↓
As per given diagram we can say
σ2>σ1;ρ1<σ1 & σ2>σ2
⇒ρ2>σ2>σ1>ρ1
∴ if we put P in L2 where V→P∝1η2 when ρ1<σ1
∴F→viscous ↓
∴V→P ↑
∴ if we put Q in L1 where V→Q∝1η1 when ρ2<σ1
∴F→viscous ↑
∴V→P ↓
⇒V→PV→Q=η1η2 & V→P.V→Q<0

Stream:JEE_ADVSubject:PhysicsTopic:FluidSubtopic:Viscosity
⏱ 2mℹ️ Source: PYQ_2015

Doubts & Discussion

Loading discussions...