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PhysicsFluidViscosityHard2 minPYQ_2015
PhysicsHardmultiple choice

Two spheres P and Q of equal radii have densities ρ1 and ρ2 , respectively. The spheres are connected by a massless string and placed in liquids L1 and L2 of densities σ1 and σ2 and viscosities η1 and η2 , respectively. They float in equilibrium with the sphere P in L1 and sphere Q in L2 and the string being taut (see figure). If sphere P alone in L2 has terminal velocity VP and Q alone in L1 has terminal velocity VQ , then

Options:(select one or more)

Answer:
A, D
Solution:

Consider a body of density ρb kept in density ρl whose viscosity is η and terminal velocity V. then



Fviscous +Fmg+FBuoyancy=0
Fviscous+ρb43πR3-j^+ρl43πR3j^=0
 Fviscous=ρb-ρl43πR3j^6πηRV=ρb-ρl43πR3 
if ρb>ρ1 then FviscousV1η & if ρb<ρl
Fviscous 
As per given diagram we can say
σ2>σ1;ρ1<σ1 & σ2>σ2
ρ2>σ2>σ1>ρ1
if we put P in L2 where VP1η2 when ρ1<σ1
Fviscous 
VP 
if we put Q in L1 where VQ1η1 when ρ2<σ1
Fviscous 
VP 
VPVQ=η1η2 & VP.VQ<0

Stream:JEE_ADVSubject:PhysicsTopic:FluidSubtopic:Viscosity
2mℹ️ Source: PYQ_2015

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