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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionMedium2 minPYQ_2013

PhysicsMediumsingle choice

A long glass capillary tube is dipped in water. It is known that water wets glass. The water level rises by $h$ in the tube. The tube is now pushed down so that only a length $h /2$ is outside the water surface. The angle of contact at the water surface at the upper end of the tube will be

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Answer:

Solution:

Here, $h = \frac{2 s c o s 0 ^{\circ}}{r ρ g} = \frac{2 s}{r ρ g}$ According to question, $\frac{h}{2} = \frac{2 s c o s θ ^{'}}{rpg}$ Dividing eq. (ii) by (i) we get, $\frac{1}{2} = cos θ^{'}$ or $θ^{'} = 6 0^{\circ}$

Stream:VITEEESubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2013

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