A capillary tube of radius r is immersed in water and water rises in it to a height h . The mass of water in the capillary tube is 5 g . Another capillary tube of radius 2 r is immersed in water. The

Question

A capillary tube of radius r is immersed in water and water rises in it to a height h . The mass of water in the capillary tube is 5 g . Another capillary tube of radius 2 r is immersed in water. The mass of water that will rise in this tube is

TestHub · Accepted Answer

: h = r ρ g 2 S c o s θ ​ Mass of water in the first tube, m = ​ π r 2 h ρ = π r 2 × ( r ρ g 2 S cos θ ​ ) × ρ = g 2 π r S cos θ ​ ​ ∴ m ∝ r . Hence, m m ′ ​ = r 2 r ​ = 2 or m ′ = 2 m = 2 × 5 g = 10 g .

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