Physics - Fluid Question with Solution | TestHub

The shape of water layer between the two plates is shown in the figure.Thickness $d$ of the film $=0.12\mathrm{mm}$ $=0.012\mathrm{cm}$ Radius $R$ of the cylindrical face $=\frac{d}{2}$ Pressure difference across the surface $=\frac{T}{R}=\frac{2T}{d}$ Area of each plate wetted by water $=A$ Force $F$ required to separate the two plates is given by $F=$ pressure difference $\times$ area $=\frac{2T}{d}A$ Putting the given values, we get $F=\frac{2\times 75\times 8}{0.012}=10^5$ dyne