Neon-23 undergoes beta decay in the following way:
Atomic masses of ²³Ne and ²³Na are $22.9945 u$ and $22.9898 u$ respectively. Determine the minimum KE of $β^{-}$ particle in $1 u = 931.5 M e V / c^{2}$ .

Question

Neon-23 undergoes beta decay in the following way: Atomic masses of ²³Ne and ²³Na are 22.9945 u and 22.9898 u respectively. Determine the minimum KE of β − particle in 1 u = 931.5 M e V / c 2 .

TestHub · Accepted Answer

Energies of β − particles lie between zero and Q-value of reaction. Hence E m i n ​ = 0

Physics - Error Question with Solution | TestHub

Doubts & Discussion

JEE Advanced (2028)