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Physics - Error Question with Solution | TestHub

PhysicsErrorMiscellaneousMedium2 minQB

PhysicsMediumnumerical

$P = \frac{4 π ^{2} A ^{3} B ^{2}}{C D}$ . Percentage errors in A, B, C and D are respectively $1%$ , $3%$ , $2%$ and $4%$ . The calculated P is $3.763$ . Find the maximum absolute error in P to two significant figures.

Answer:

0.53

Solution:

$\frac{Δ P}{P} = 3 \frac{Δ A}{A} + 2 \frac{Δ B}{B} + \frac{1}{2} \frac{Δ C}{C} + \frac{Δ D}{D}$ .

Maximum percentage error $= 3 (1) + 2 (3) + \frac{1}{2} (2) + 4 = 14%$ .

$Δ P = 0.14 (3.763) = 0.52682$ .

To two significant figures, $Δ P = 0.53$ .

Stream:JEESubject:PhysicsTopic:ErrorSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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