Physics - Error Question with Solution | TestHub

Step 1: Determine the required Vernier Scale Division (VSD)

The least count of a Vernier calliper is

$$LC=MSD-VSD.$$

Given:

$$MSD=0.1cm,LC=0.02cm.$$

Thus,

$$0.02=0.1-VSD,$$

$$VSD=0.1-0.02=0.08cm.$$

Step 2: Relate VSD to total length $m$ and number of divisions $n$

The total vernier length is

$$m=n\times VSD.$$

Step 3: Check the given options

Since $VSD=0.08cm$:

* Option (A): $n=10,m=0.5$

$$m=10\times 0.08=0.8\ne \mathrm{0.5.}$$

* Option (B): $n=9,m=0.4$

$$m=9\times 0.08=0.72\ne \mathrm{0.4.}$$

* Option (C): $n=10,m=0.8$

$$m=10\times 0.08=0.8,$$

which matches.

* Option (D): $n=10,m=0.2$

$$m=10\times 0.08=0.8\ne \mathrm{0.2.}$$