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Physics - Error Question with Solution | TestHub

PhysicsErrorMiscellaneousMedium2 minQB

PhysicsMediumstatement

Select the correct statement about these instruments. (i) Vernier callipers: main scale division $= 0.05 cm$ , vernier scale division $= \frac{2.45}{50} cm$ . (ii) Screw gauge: pitch $= 0.5 mm$ ; each circular scale division measures $0.01 mm$ .

Options:

Answer:

Solution:

$LC_{V} = 0.05 - \frac{2.45}{50} = 0.001 cm = 0.01 mm$ .

$LC_{S} = 0.01 mm$ . Their least counts are equal.

Stream:JEESubject:PhysicsTopic:ErrorSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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