Physics - Error Question with Solution | TestHub

The period of oscillation of a simple pendulum is$T=2\pi \sqrt{\frac{L}{g}}.$Measured value of$L$is$1.0 \mathrm{m}$from meter scale having a minimum division of$1 \mathrm{mm}$and time of one complete oscillation is$1.95 \mathrm{s}$measured from stopwatch of$0.01 \mathrm{s}$resolution. The percentage error in the determination of$\text{'}g\text{'}$will be: