The current in a circuit containing a capacitance C and a resistance R in series leads over the applied voltage of frequency 2 π ω by

Question

The current in a circuit containing a capacitance C and a resistance R in series leads over the applied voltage of frequency 2 π ω ​ by

TestHub · Accepted Answer

Solution:

In an RC series circuit, the phase angle $ϕ$ between the voltage and current is given by $tan ϕ = \frac{X _{C}}{R}$ , where $X_{C} = \frac{1}{ω C}$ is the capacitive reactance.

Thus, $tan ϕ = \frac{1}{ω CR}$ .

Therefore, $ϕ = tan^{- 1} (\frac{1}{ω CR})$ .

In an RC circuit, the current leads the voltage.

The final answer is $A$ .

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