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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsEasy2 minQB

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A series LCR circuit driven by $300 V$ at a frequency of $50 Hz$ contains a resistance $R = 3 k Ω$ , an inductor of inductive reactance $X_{L} = 250 π Ω$ and an unknown capacitor. The value of capacitance to maximise the average power should be:

$(take π^{2} = 10)$

Options:

Answer:

Solution:

Angular frequency, $ω = 2 π f = 2 π \times 50 = 100 π r a d s^{- 1}$ At resonance,

$X_{C} = X_{L} \Rightarrow \frac{1}{ω C} = ω L \Rightarrow \frac{1}{ω C} = 250 π \Rightarrow C = \frac{1}{100 π \times 250 π} F = 4 μF$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: QB

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