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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSelf and mutual inductorEasy2 minQB

PhysicsEasynumerical

A part of a complete circuit is shown in the figure. At some instant, the value of current I is $1 A$ and it is decreasing at a rate of $1 0^{2} As^{- 1}$ . The value of the potential difference $V_{p} - V_{Q},$ (in volts) at that instant is-

Answer:

33.00

Solution:

$V_{p} - L \frac{d l}{d t} - 30 + R I = V_{Q}$

$V_{P} - V_{a} = + 50 \times 1 0^{- 3} \times 1 0^{2} + 30 - 1 \times 2$

$= + 5 + 30-2 = 33$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Self and mutual inductor

⏱ 2mℹ️ Source: QB

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