The power factor of the circuit is 13 6 n , find n.

V L − V C = 50 and V R 2 + 5 0 2 = 13 0 2 , so V R = 120 V Power factor = V V R = 130 120 = 13 12 = 13 6 n , so n = 2 Answer 2.00

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PhysicsEMI/AC271Medium2 minQB

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Passage / Comprehension

In the RLC series circuit shown, the readings of voltmeters are $V_{1} = 150 V, V_{2} = 50 V$ and the source has emf 130 V .\\

The power factor of the circuit is $\frac{6 n}{13}$ , find n.

Answer:

2.00

Solution:

$V_{L} - V_{C} = 50$ and $V_{R}^{2} + 5 0^{2} = 13 0^{2}$ , so $V_{R} = 120 V$

Power factor = $\frac{V _{R}}{V} = \frac{120}{130} = \frac{12}{13} = \frac{6 n}{13}$ , so n = 2

Answer 2.00

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:271

⏱ 2mℹ️ Source: QB

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