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PhysicsEMI/ACAC current and voltageEasy2 minQB

PhysicsEasysingle choice

An alternating voltage source $V = 260 sin (628 t)$ is connected across a pure inductor of $5 mH$ . Inductive reactance in the circuit is:

Answer:

Solution:

Comparing the given equation of AC voltage with standard expression, $V = V_{0} sin (ω t)$ , we get $ω = 628 r a d s^{- 1}$ .

Inductive reactance is given by, $X_{L} = ω L$ .

$= 628 \times (5 \times 1 0^{- 3})$

$= 3.14Ω$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:AC current and voltage

⏱ 2mℹ️ Source: QB

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