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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACMotional & Rotational EMFMedium2 minQB

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A rod of length 10 cm made up of conducting and non-conducting material (shaded part is non-conducting). The rod is rotated with constant angular velocity 10 rad/sec about point O, in constant magnetic field of 2 tesla as shown in the figure. The induced emf between the point A and B of rod will be :-

Options:

Answer:

Solution:

Only the conducting segment AB contributes to the potential difference between A and B.

$r_{A} = 0.10 m, r_{B} = 0.07 m$

$E = \frac{B ω}{2} (r_{A}^{2} - r_{B}^{2})$

$E = \frac{2 \times 10}{2} (0.1 0^{2} - 0.0 7^{2}) = 0.051 V$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Motional & Rotational EMF

⏱ 2mℹ️ Source: QB

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