Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACSeries AC CircuitsMedium2 minQB

PhysicsMediumsingle choice

The power factor of circuit is $1/ 2$ . The capacitance of the circuit is equal to :-

Answer:

Solution:

The power factor fixes the magnitude of the net reactance.

$\frac{R}{Z} = \frac{1}{2} \Rightarrow ∣ X_{L} - X_{C} ∣ = R = 10 Ω$

$X_{L} = ω L = 100 \times 0.1 = 10 Ω$

For a finite capacitance, the capacitive branch gives the following result.

$X_{C} = 20 Ω, C = \frac{1}{ω X _{C}} = 500 μ F$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Series AC Circuits

⏱ 2mℹ️ Source: QB

Loading discussions...