For the circuit shown in figure, R 1 = 30 ( 5 ) ohm, R 2 = 10 ( 5 ) ohm, C 1 = C 2 = 18 micro farad, and L 1 = L 2 = 1 mili henry. The electromotive force of the battery is E = 10 volt

Question

For the circuit shown in figure, R 1 ​ = 30 ( 5 ​ ) ohm, R 2 ​ = 10 ( 5 ​ ) ohm, C 1 ​ = C 2 ​ = 18 micro farad, and L 1 ​ = L 2 ​ = 1 mili henry. The electromotive force of the battery is E = 10 volt. The voltmeter connected in circuit is an ideal voltmeter. Initially the switch is closed and the system is under steady state. Key opened at t = 0 . Column I Column II P Reading of voltmeter at steady state (just before t = 0 ) is V 1 ​ volt then ∣ V 1 ​ ∣ 1 10 Q Reading of voltmeter just after key opened (just after t = 0 ) is V 2 ​ volt then ∣ V 2 ​ ∣ 2 100 R Total heat dissipated in resistor R 1 ​ after key opening.(after t = 0 ) is H 1 ​ micro joule. then H 1 ​ is 3 1000 S Total heat dissipated in resistor R 2 ​ after key opening.(after t = 0 ) is H 2 ​ micro joule. then H 2 ​ is 4 50 5 20

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L 2 At steady state L 2 Just after t = 0

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Doubts & Discussion

Column I	Column II
P Reading of voltmeter at steady state (just before $t = 0$ ) is $V_{1}$ volt then $∣ V_{1} ∣$	1 10
Q Reading of voltmeter just after key opened (just after $t = 0$ ) is $V_{2}$ volt then $∣ V_{2} ∣$	2 100
R Total heat dissipated in resistor $R_{1}$ after key opening.(after $t = 0$ ) is $H_{1}$ micro joule. then $H_{1}$ is	3 1000
S Total heat dissipated in resistor $R_{2}$ after key opening.(after $t = 0$ ) is $H_{2}$ micro joule. then $H_{2}$ is	4 50
	5 20