Start Free Mock LoginAlready registered? Login here

Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACFaraday law/Lenz lawMedium2 minQB

PhysicsMediumsingle choice

A long solenoid of radius $R$ carries a time $(t)$ dependent current $I (t) = I_{0} t (1 - t)$ . A ring of radius $2 R$ is placed coaxially near its middle. During the time interval $0 \leq t \leq 1,$ the induced current $(I_{R})$ and the induced $E M F (V_{R})$ in the ring change as:

Options:

Answer:

Solution:

$I = I_{0} t - I_{0} t^{2}$
$ϕ = B A$
$ϕ = μ_{0} n I A$
$V_{R} = - \frac{d ϕ}{d t} = - μ_{0} n A I_{0} (1 - 2 t)$
$V_{R} = 0$ at $t = \frac{1}{2}$
And $I_{R} = \frac{V_{R}}{R e s i s t a n c e o f l o o p} = 0$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Faraday law/Lenz law

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...