In a circuit, an inductance of 0.1 Henry and a resistance of 1 Ω are connected in series with an a.c. source of voltage V = 5 sin 10 t . The phase difference between the current and applied voltage wi

Question

In a circuit, an inductance of 0.1 Henry and a resistance of 1 Ω are connected in series with an a.c. source of voltage V = 5 sin 10 t . The phase difference between the current and applied voltage will be

TestHub · Accepted Answer

The phase difference ϕ is given by tan ϕ = R X L ​ ​ = R ω L ​ = 1 10 × 0.1 ​ = 1 . Thus, ϕ = tan − 1 ( 1 ) = 4 π ​ . Therefore, the phase difference between the current and applied voltage is 4 π ​ . Concepts used: Inductive reactance, phase difference in RL circuit.

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