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Physics - EMI/AC Question with Solution | TestHub

PhysicsEMI/ACMotional & Rotational EMFMedium2 minQB

PhysicsMediumnumerical

Consider a circuit shown in the figure. The rod is free to slide over the resistanceless vertical rails. Maximum charge on the capacitor C is given by $q \times 1 0^{- 5}$ coulomb. Fill the value of q. [Given : $m = 0.1 kg, R = 10Ω, C = 24 μ F, B = 1 T & ℓ = 8 m, g = 10 m / s^{2}$ ]

Answer:

3.00

Solution:

Ans (3.00)

At equilibrium $m g = i ℓ B$

$m g = \frac{B v ℓ}{R} \times ℓ B \Rightarrow (e) = \frac{m g R}{ℓ B}$

$q_{ma x} = C Δ v = \frac{C \times m g R}{ℓ B} = \frac{24 \times 1 0 ^{- 6} \times 0.1 \times 1 \times 10 \times 10}{8 \times ( 1 )} = 3 \times 1 0^{- 5}$

Stream:JEESubject:PhysicsTopic:EMI/ACSubtopic:Motional & Rotational EMF

⏱ 2mℹ️ Source: QB

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